If 0.40 mol of a gas in a 3.7 L container is held at a pressure of 175 kPa, what is the temperature of the gas?
1 Answer
Mar 18, 2017
PV = nRT
Where
P = pressure
V = volume
n = moles
R is the gas constant with a value of
=
T = temperature in Kelvin
Therefore
Plug in the variables but 175kPa to atm
1kilopascal = 0.00986923atm
Thus 175kilopascal
=
= 194.690888736K