Question

If 1 g of water has a volume of 1 mL what would the mass of 1 L of water weigh in kilograms?

Answer 1

You have specified the density, `rho`, by these parameters. And we know that `1*g=10^-3*kg` or that `10^3*g=1*kg`

Explanation:

And `rho` `=` `"Unit mass"/"Unit volume"`

Here `rho` `=` `(1*g)/(1*mL)` `=` `1*g*mL^-1`

i.e. `"mass"` `=` `"Volume"xxrho` `=`

`1*cancelLxx10^3*cancel(mL)*cancel(L^-1)xx1*g*cancel(mL^-1)`

`=` `10^3*cancelgxx10^-3*kg*cancel(g^-1)`

`=` `1*kg`