Question

If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration?

Answer 1

The concentration of the HCl is 0.20 mol/L.

There are two steps to this calculation.

1. Calculate the moles of HCl.
2. Calculate the molarity of the solution.

Step 1.

`PV = nRT`

`n = (PV)/(RT) = (100"kPa" × 0.100"L")/(8.314"kPa·L·K⁻¹mol⁻¹" × 300"K")` = 4.01 × 10⁻³ mol

Step 2.

Molarity = #"moles of solute"/"litres of solution" = (4.01 × 10⁻³"mol")/(0.020"L")# = 0.20 mol/L

The concentration of the HCl is 0.20 mol/L.