Question

If 2.0 mL of 6.0M HCl is used to make a 500.0-mL aqueous solution, what is the molarity?

Answer 1

`"Molarity"="Moles of solute"/"Volume of solution"=0.024*mol*L^-1`

Explanation:

And thus..........`(6.0*mol*L^-1xx2.0xx10^-3*L)/(0.500*L)`

`=0.024*mol*L^-1`.

What is `pH` of this solution?

I forgot to remind you that the order of addition is important. While it is not crucial here, you ALWAYS add ACID to water, and never the reverse! Why? [See here..........](https://socratic.org/questions/which-is-correct-adding-sodium-hydroxide-to-water-or-adding-water-to-solid-sodiu)