If 22.5 L of nitrogen at 748 mm Hg are compressed to 725 mm Hg at constant temperature, what is the new volume?

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Answer 1 · 2016-12-06T08:21:38

The new volume $= 23.2 L$ $=23.2 L$

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$

$P_{1} = 748 m m H g$ $P_1=748 mm Hg$

$V_{1} = 22.5 L$ $V_1=22.5 L$

$P_{2} = 725 m m H g$ $P_2=725 mm Hg$

$V_{2} = \frac{P_{1} V_{1}}{P_{2}}$ $V_2=(P_1V_1)/P_2$

$= \frac{748 \cdot 22.5}{725} = 23.2 L$ $=(748*22.5)/725=23.2 L$