If $2 a - 8 = 4$ $2a-8=4$ and $3 b - 8 = 10$ $3b-8=10$ , what is the value of $a + b$ $a+b$ ?

Question

4819 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-03T22:33:34

$a + b = 12$ $a + b = 12$

Solve the first equation for $a$ $a$ :

$2 a - 8 = 4$ $2a - 8 = 4$

$2 a - 8 + 8 = 4 + 8$ $2a - 8 + 8 = 4 + 8$

$2 a = 12$ $2a = 12$

$2 \frac{a}{2} = \frac{12}{2}$ $2a/2 = 12/2$

$a = 6$ $a = 6$

Solve the second equation for $b$ $b$ :
$3 b - 8 = 10$ $3b - 8 = 10$

$3 b - 8 + 8 = 10 + 8$ $3b - 8 + 8 = 10 + 8$

$3 b = 18$ $3b = 18$

$3 \frac{b}{3} = \frac{18}{3}$ $3b/3 = 18/3$

$b = 6$ $b = 6$

Therefore:

$a + b = 6 + 6$ $a + b = 6 + 6$

$a + b = 12$ $a + b = 12$

If 2a−8=42a-8=4 and 3b−8=103b-8=10, what is the value of a+ba+b?