If f(x) = (5/2)x^(2/3) - x^(5/3)f(x)=(52)x23x53, what are the points of inflection, concavity and critical points?

1 Answer
Nov 7, 2016

f(x) = (5/2)x^(2/3) - x^(5/3)f(x)=(52)x23x53

The domain of ff is (-oo,oo)(,).

f'(x) = (5/3)x^(-1/3) - 5/3 x^(2/3)

= 5/3[x^(-1/3) - x^(2/3)]

= 5/3[(1-x)/x^(1/3)]

f' does not exist at x=0 and f'(x) = 0 at x=1.
Both 0 and 1 are in the domain of f, so both are critical numbers.

f''(x) = 5/3[-1/3x^(-4/3)-2/3x^(-1/3)]

= -5/9x^(-4/3)[1+2x]

= -(5(1+2x))/(9x^(4/3))

f''(x) > 0 for x < -1/2 and

f''(x) > 0 for -1/2 < x < 0 and x > 0

The graph of f is concave up on (-oo,-1/2) and concave down on (-1/2,0) and on (0,oo).

The point (-1/2,f(-1/2)) is an inflection point.