If #a_0=7# and #a_(n+1)=a_n+12# for #n>=0#, how do you find the values of #a_5#?

1 Answer
Jan 7, 2017

#a_5 = 55#

Explanation:

This recursive definition describes an arithmetic sequence with initial term #7# and common difference #12#.

The general term of an arithmetic sequence can be written:

#a_n = a+d(n-1)#

where #a# is the initial term and #d# the common difference.

So in our example, #a=7#, #d = 12# and:

#a_5 = a+d(5-1) = a+4d = 7+4*12 = 7+48 = 55#