If (a+1)/(b-1)=5/1a+1b−1=51 and (a-1)/(b+1)=1/1a−1b+1=11, how do you find the value of b/a?
1 Answer
Mar 27, 2018
Explanation:
We can see that
a + 1 = 5(b - 1)a+1=5(b−1)
a + 1 = 5b -5a+1=5b−5
6 = 5b - a6=5b−a
And
a - 1 = b + 1a−1=b+1
a - 2= ba−2=b
Substituting the second equation into the first we get
6 = 5(a- 2) - a6=5(a−2)−a
6 = 5a - 10 - a6=5a−10−a
16 = 4a16=4a
a = 4a=4
It follows that
Therefore
Hopefully this helps!