Question

If a `2 kg` object is constantly accelerated from `0m/s` to `15 m/s` over `12s`, how much power musy be applied at `t= 1`?

Answer 1

`"18.75 watts"` is the power constantly applied.

Explanation:

First, find the total energy at the end, in this case kinetic energy

`1/2×"2kg"× ("15 m/s")^2 = "225 joules"`

Then divide `"225 joules"` by the time in seconds to get the average power in watts:

`"225 Joule"/"12 s" = "18.75 watts"`