If a 2 kg object is constantly accelerated from 0m/s to 15 m/s over 12s, how much power musy be applied at t= 6 ?

1 Answer
Sep 10, 2017

The power is =18.75W

Explanation:

The acceleration is

a=(v-u)/t=(15-0)/12=15/12=1.25ms^-2

According to Newton's Second Law

The force is

F=ma=2*1.25=2.5N

The speed at t=6s is

v=u+at=0+1.25*6=7.5ms^-1

The power is

P=Fv=2.5*7.5=18.75W