If a #2# #kg# object accelerates constantly from #0# #ms^-1# to #15# #ms^-1# over #6# #s#, how much power must be applied at #t=4#?

Question

1364 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-18T06:19:05

The power is #=50W#

#a=(v-u)/t=(15-0)/6=2.5ms^-2#

The mass is #m=2kg#

the force is #F=ma#,

#F=2*2.5=5N#

The velocity at #t=4s# is

#v=u+at=0+2.5*4=10ms^-1#

The power is

#P=Fv=5*10=50W#