If A = <4 ,2 ,5 >A=<4,2,5>, B = <6 ,2 ,8 >B=<6,2,8> and C=A-BC=AB, what is the angle between A and C?

1 Answer
Feb 19, 2016

2.82 radians≈ 162^@162

Explanation:

To calculate the angle between 2 vectors ula " and " ulc
the following should be used.

costheta = (ula . ulc)/(|ula||ulc|)

here C= A - B = (4,2,5) - (6,2,8) = (-2,0,-3)

now ula . ulc = (4,2,5) . (-2,0,-3)

=(4xx-2) + (2xx0) + (5xx-3)

= -8 + 0 -15 = - 23

|ula| = sqrt(4^2+2^2+5^2) = sqrt(16+4+25) = sqrt45

and |ulc| = sqrt((-2)^2+0+(-3)^2) = sqrt(4+0+9) = sqrt13

rArr theta = cos^-1(-23/(sqrt45 xx sqrt13)) ≈ 2.82 " radians"