If A=<5,2,8>, B=<2,5,6> and C=A−B, what is the angle between A and C?

1 Answer
Narad T.
Feb 22, 2017

The angle is =56.4º

Explanation:

et's start by calculating

→C=→A−→B

→C=⟨5,2,8⟩−⟨2,5,6⟩=⟨3,−3,2⟩

The angle between →A and →C is given by the dot product definition.

→A.→C=∥→A∥⋅∥→C∥cosθ

Where θ is the angle between →A and →C

The dot product is

→A.→C=⟨5,2,8⟩.⟨3,−3,2⟩=15−6+16=25

The modulus of →A= ∥∥⟨5,2,8⟩∥=√25+4+64=√93

The modulus of →C= ∥∥⟨3,−3,2⟩∥=√9+9+4=√22

So,

cosθ=→A.→C∥∥∥→A∥⋅∥→C∥∥∥=25√93⋅√22=0.55

θ=56.4º

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