If a acceleration-time graph has a static trend, i.e., neither moving up or down (starting at (0,50) and (for the purposes of the graph) ending at (10,50), then what would the velocity-time and distance-time graphs look like?
1 Answer
See attached pic
Explanation:
Assuming the object begins from rest with initial velocity zero and proceeds in the positive direction with uniform acceleration of 50 m/s^2, then since by definition, velocity is the rate of change in displacement, and acceleration is the rate of change in velocity, the corresponding graphs will look as shown below.
The values o the axes have ben found by sing the equations of motion for constant acceleration in 1 direction.
Note also that the area under the acceleration-time graph represents the change in velocity, the gradient of the velocity-time graph represents the acceleration, ad the area under the velocity-time graph represents the change in displacement. The instantaneous gradient at any point on the displacement-time graph represents the instantaneous velocity at that point.
