If a ball is initially dropped from height h and has coefficient of restitution 0.9 .How many bounced will the ball make before comping to rest? Please help...

1 Answer
Jun 5, 2018

See below

Explanation:

If the ball was dropped from a height #h#, then it originally had gravitational potential energy relative to ground, of:

  • #U = m g h#.

So, just before it's first collision with ground, the ball will have kinetic energy #T#, such that:

  • #T = mgh #

The Coefficient of Restitution, #e#, as it applies between 2 bodies [here, ground and ball], is related to kinetic energy, as:

# e= sqrt ( {sum T_("post-collision"))/{sum T_("pre-collision")} )#

In the reference frame of ground, only the ball has Kinetic Energy.

#implies e= sqrt ( (T')/T ) = 0.9#

#implies T' = T * 0.9^2#

#implies mg h' = mgh * 0.9^2#

#implies h' = 0.81 h #

And so #h'# is the height to which the ball will rise after the first collision with ground

So:

  • # h_1 = 0.81 h_o #

Follows that:

  • # h_2 = 0.81 h_1 = 0.81^2 h_o #

  • # h_3 = 0.81 h_2 = 0.81^3 h_o #

  • # ... #

  • # h_n = 0.81^n h_o #

In this highly idealised model, the ball will never come to rest, ie #h_n = 0# requires that #n to oo#.