If a ball is initially dropped from height h and has coefficient of restitution 0.9 .How many bounced will the ball make before comping to rest? Please help...

1 Answer
Jun 5, 2018

See below

Explanation:

If the ball was dropped from a height h, then it originally had gravitational potential energy relative to ground, of:

  • U = m g h.

So, just before it's first collision with ground, the ball will have kinetic energy T, such that:

  • T = mgh

The Coefficient of Restitution, e, as it applies between 2 bodies [here, ground and ball], is related to kinetic energy, as:

e= sqrt ( {sum T_("post-collision"))/{sum T_("pre-collision")} )

In the reference frame of ground, only the ball has Kinetic Energy.

implies e= sqrt ( (T')/T ) = 0.9

implies T' = T * 0.9^2

implies mg h' = mgh * 0.9^2

implies h' = 0.81 h

And so h' is the height to which the ball will rise after the first collision with ground

So:

  • h_1 = 0.81 h_o

Follows that:

  • h_2 = 0.81 h_1 = 0.81^2 h_o

  • h_3 = 0.81 h_2 = 0.81^3 h_o

  • ...

  • h_n = 0.81^n h_o

In this highly idealised model, the ball will never come to rest, ie h_n = 0 requires that n to oo.