Question

If a gas at occupies 2.60 liters at a pressure of 1.00 atm, what will be its volume at a pressure of 3.50 atm?

Answer 1

Approx. `3/4*L.`

Explanation:

`"Boyle's Law"` gives us the relationship `Pprop1/V` for constant `T`, and for constant amount of gas.

Thus `PV=k`. For constant temperature, and constant amount of gas, as pertains in this scenario, we write:

`P_1V_1=P_2V_2`

And thus `V_2=(P_1V_1)/(P_2)=(2.60*Lxx1.00*atm)/(3.50*atm)=??L`.

The best thing about using these simple experimental laws of proportionality is that we can persist with using intuitively easy units such as `"litres"` and `"atmospheres"`. It is intuitively obvious that the volume of a gas sample under compression should reduce.