If a gas has an initial temperature of 300 K at a pressure of 100 kPa and it is then heated to 600 K, what is the new pressure?

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Answer 1 · 2016-08-26T01:43:05

The new pressure is $200 k P a$ $200 kPa$

This question requires you to use Gay-Lussac's law:

$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$ $P_1/T_1 = P_2/T_2$

The number 1 represents the initial conditions and the number 2 represents the final conditions.

Identify your known and unknown variables:

$Knowns:$ $color(blue)("Knowns:"$

$P_{1}$ $P_1$ = 100kPa
$T_{1}$ $T_1$ = 300K
$T_{2}$ $T_2$ = 600K

$Unknowns:$ $color(magenta) ("Unknowns:"$

$P_{2}$ $P_2$

Rearrange the equation to solve $P_{2}$ $P_2$

$P_{2} = \frac{P_{1} \times T_{2}}{T_{1}}$ $P_2=(P_1xxT_2)/T_1$

Plug in your given values to obtain the final pressure:

$P_2=(100 kPaxx600cancelK)/(300cancelK)$ = $200 kPa$