If a gas sample has a pressure of 30.7 kPa at 0.00°C, by how much does the temperature have to decrease to lower the pressure to 28.4 kPa?

1 Answer

T_2 = -20.5^@ "C"T2=20.5C

Explanation:

In this question I assume that the volume is unchanged and therefore, we can use the following law:

P/T=kPT=k

Then, (P_1)/(T_1)=(P_2)/(T_2)=>T_2=(T_1)/(P_1)xxP_2P1T1=P2T2T2=T1P1×P2

=>P_2=("273.15 K")/(30.7cancel("kPa"))xx28.4cancel("kPa") = "252.69 K"

Therefore, the temperature should be lowered to: 252.69 - 273.15 = - 20.464^@ "C"

=> color(blue)(T_2 = -20.5^@"C") to 3 sig figs.