If a polymer is made of ten monomers, how many water molecules will be needed to break all the bonds? Why?

Question

If a polymer is made of ten monomers, how many water molecules will be needed to break all the bonds? Why?

1 Answer

Impact of this question

50568 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-08-30T19:22:31

nine assuming you are breaking only the bonds where the water molecule is released when the bonds are formed.

Explanation:

lets break the problem like this. Following is a diagrammatic representation of 10 monomer polymer

$A_{1} - A_{2} - A_{3} - A_{4} - A_{5} - A_{6} - A_{7} - A_{8} - A_{9} - A_{10}$ $A_1-A_2-A_3-A_4-A_5-A_6-A_7-A_8-A_9-A_10$

here each polymer bond is shown as " $-$ $-$ "

polymer bond is formed when $- O H$ $-OH$ group from 1st monomer and $H$ $H$ group from 2nd monomer is removed as $H_{2} O$ $H_2O$

now to separate the two monomer you require only one water molecule.
$A_{1} - A_{2} + H_{2} O \to A_{1} + A_{2}$ $A_1-A_2 +H_2O →A_1 + A_2$

for three monomer polymer we have 2 bonds so we require two water molecules. now for 10 monomer polymer we have 9 polymer bonds so we require 9 water molecules.

Science

Math

Humanities

... and beyond

If a polymer is made of ten monomers, how many water molecules will be needed to break all the bonds? Why?

1 Answer

Explanation:

Related questions

Impact of this question