Question

If a projectile is shot at a velocity of `2 m/s` and an angle of `pi/3`, how far will the projectile travel before landing?

Answer 1

`sqrt(3)/4.9 "m"`

Explanation:

Range (`R`) of a projectile is given by the formula

`R = (u^2sin(2theta))/g`

`R = (("2 m/s")^2 × sin((2pi)/3))/("9.8 m/s"^2) = ("4 m"^2//"s"^2 × sqrt(3)/2)/("9.8 m/s"^2) = sqrt(3)/4.9 "m"`