If a rocket with a mass of 2500 tons vertically accelerates at a rate of # 7/3 ms^(-2)#, how much power will the rocket have to exert to maintain its acceleration at 5 seconds?

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Answer 1 · 2018-04-05T14:42:14

The power is #=350MW#

The mass of the rocket is #m=2500000kg#

The acceleration of the rocket is #a=7/3ms^-2#

The acceleration due to gravity is #=9.8ms^-2#

According to Newton's second Law of Motion, the net force on the rocket is

#F=m(a+g)=2500000*(9.8+7/3)=30333333N#

Assuming that the initial velocity of the rocket is #u=0ms^-1#

The velocity after #t=5s# is

#v=u+at=0+7/3*5=11.67ms^-1#

The power is

#P=Fv=30333333*11.67=350000000W=350MW#