If a rocket with a mass of 3900 tons vertically accelerates at a rate of $15/8 m/s^2$ , how much power will the rocket have to exert to maintain its acceleration at 5 seconds?

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Answer 1 · 2017-11-10T02:16:03

$34 × 10^7 color(white)(‘) "Watt"$

Velocity of rocket after 5 seconds is
$v = u + at = 0 + (15/8"m/s"^2 × "5 s") = "9.375 m/s"$

By work energy theorem
Work done by rocket = Kinetic energy gained by it in 5 seconds

$"Power" = "Work"/"Time" = (1/2mv^2)/t$

$= (1/2 × 3900 × 10^3 "kg" × ("9.375 m/s")^2) / "5 s"$

$= 34 × 10^7 color(white)(‘) "Watt"$

If a rocket with a mass of 3900 tons vertically accelerates at a rate of 15/8 m/s^2 15/8 m/s^2, how much power will the rocket have to exert to maintain its acceleration at 5 seconds?