If a rocket with a mass of 4000 tons vertically accelerates at a rate of # 12/5 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 11 seconds?

Question

1442 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-22T05:49:37

The power is #=253.44MW#

We apply Newton's Second Law to find the force

#F=ma#

The mass is #m=4000*1000kg=4*10^6kg#

The acceleration is #a=12/5ms^-2#

The force is

#F=ma=4*10^6*12/5=9.6*10^6N#

We apply the equation of motion

#v=u+at#

to calculate the speed at #t=11s#

#v=0+12/5*11=26.4ms^-1#

The power is

#P=Fv#

#P=9.610^6*26.4=253.44*10^6W#

#=253.44MW#