If a rocket with a mass of #700 kg# vertically accelerates at a rate of # 3/2 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 4 seconds?
1 Answer
Jan 29, 2017
P=6.3 KW
Explanation:
see
MASS=700 kg
Acceleration=
THEREFORE force exerted is
Now
so by this we can get
therefore
dividing both sides of the equation by
And by definition power is energy per unit time and velocity is displacement per unit time.so applying these