Question

If a spring has a constant of `6 (kg)/s^2`, how much work will it take to extend the spring by `43 cm`?

Answer 1

`W=E_p=0,5547 J`

Explanation:

`"It has the potential energy ,if spring extends"`
`W=E_p=1/2*k*Delta x^2`
`W=E_p=1/2*6*(0,43)^2`
`43 cm=0,43 m`
`W=E_p=3*0,1849`
`W=E_p=0,5547 J`