Question

If a spring has a constant of `7 (kg)/s^2`, how much work will it take to extend the spring by `52 cm`?

Answer 1

The work done is `=0.95J`

Explanation:

The spring constant is `k=7kgs^-2`

The extension is `x=0.52m`

The work done to extend the spring is equal to the potential energy of the spring.

`W=1/2kx^2=1/2*7*0.52^2=0.95J`