If a spring has a constant of 7 (kg)/s^2, how much work will it take to extend the spring by 52 cm ?

1 Answer
Apr 13, 2017

The work done is =0.95J

Explanation:

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The spring constant is k=7kgs^-2

The extension is x=0.52m

The work done to extend the spring is equal to the potential energy of the spring.

W=1/2kx^2=1/2*7*0.52^2=0.95J