If #abc=27846,a/6=b+4=c-4# then #a+b+c=#?

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Answer 1 · 2017-10-29T16:03:43

From given condition we have

#a=6(c-4)#

#b=c-8#

So inserting in the 1st relation

#6(c-4)(c-8)c=27846#

#=>(c-8)xx(c-4)xxc=27846/6=4641#

#=>(c-8)xx(c-4)xxc=13xx17xx21#

Hence

#c=21,b=c-8=13and a=6(c-4)=102#

So

#a+b+c=102+13+21=136#