If an ideal gas has a pressure of 4.97 atm, a temperature of 481 K, and has a volume of 29.83 L, how many moles of gas are in the sample?

1 Answer
May 13, 2016

n~=4*mol

Explanation:

The Ideal Gas Law explicitly states that:

n=(PV)/(RT) = (4.97*cancel(atm)xx29.83*cancelL)/(0.0821*cancel(L)*cancel(atm)*cancel(K^-1)*mol^-1xx481*cancelK) = ??*mol.

Note that the only problem in solving this problem is choosing an appropriate gas constant, R. For chemists, R=0.0821*L*atm*K^-1*mol^-1, is very useful because it uses the units that chemists would typically use, i.e. "atmospheres, litres, etc.". Is the equation correct dimensionally?