If an Ideal gas has a pressure of 9.75 atm, a temperature of 323 K, and has a volume of 33.81 L, how many moles of gas are in the sample?

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Answer 1 · 2016-07-01T05:45:23

$n = \frac{P V}{R T}$ $n=(PV)/(RT)$

$P$ $P$ $=$ $=$ $9.75 \cdot a t m$ $9.75*atm$ ;

$V$ $V$ $=$ $=$ $33.81 \cdot L$ $33.81*L$

$R$ $R$ $=$ $=$ $0.0821 \cdot L \cdot a t m \cdot K^{- 1} \cdot m o l^{- 1}$ $0.0821*L*atm*K^-1*mol^-1$

$T$ $T$ $=$ $=$ $323 \cdot K$ $323*K$

You ave just got to fill in the dots to give an answer in $MOLES$ $"MOLES"$

This will be inevitable dimensionally:

$(cancel(atm)xxcancelK)/(cancelL*cancel(atm)*cancel(K^-1)*mol^-1xxcancelK)$

That is you get an answer in $1/(mol^-1)=mol" as required."$

Capisce?