If an object is moving at $10 \frac{m}{s}$ $10 m/s$ over a surface with a kinetic friction coefficient of $u_{k} = \frac{3}{g}$ $u_k=3 /g$ , how far will the object continue to move?

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Answer 1 · 2016-05-10T15:13:25

$S = 16.67 m$ $S=16.67" " m$

$Friction Force: F_{f} = U_{k} \cdot m \cdot g$ $"Friction Force: " F_f=U_k*m*g$

$F_f=3/cancel(g)*m*cancel(g)$

$F_f=3*m$

$"deceleration of object : " a=F_f/m" The Newton's second law"$

$a=(3*cancel(m))/cancel(m)$

$a=3 m/s^3$

$v_f^2=v_i^2-2*a*S$

$v_f=0$
$v_i=10m/s$
$a=3m/s^2$
$S=?$

$0=10^2-2*3*S$

$100=6*S$

$S=100/6=50/3$

$S=16.67" " m$

If an object is moving at 10 m/s10ms10 m/s over a surface with a kinetic friction coefficient of u_k=3 /guk=3gu_k=3 /g, how far will the object continue to move?