If an object is moving at $10 \frac{m}{s}$ $10 m/s$ over a surface with a kinetic friction coefficient of $u_{k} = \frac{2}{g}$ $u_k=2 /g$ , how far will the object continue to move?

Question

1523 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-20T01:22:00

$25 m$ $"25 m"$

Acceleration of object $= -μ_k"g" = -2/cancel("g") × cancel("g") = -"2 m/s"^2$

$"S" = -("u"^2)/(2a) color(white)(....)[∵ "v" = 0]$

$"S" = -(("10 m/s")^2)/(2 × (-"2 m/s"^2)) = "25 m"$

If an object is moving at 10 m/s10ms10 m/s over a surface with a kinetic friction coefficient of u_k=2 /guk=2gu_k=2 /g, how far will the object continue to move?