If an object is moving at $15 m/s$ over a surface with a kinetic friction coefficient of $u_k=5 /g$ , how far will the object continue to move?

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Answer 1 · 2017-05-24T08:10:04

The distance is $=22.5m$

Let the mass of the object be $=mkg$

Then,

the coefficient of friction is

$mu_k=F_r/N$

$N=mg$

So,

$F_r=mu_k*N=5/g*mg=5m$

$F=ma=5m$

The deceleration is $=5ms^-2$

We apply the equation of motion

$v^2=u^2+2as$

$v=0$

$u=15ms^-1$

$a=-5ms^-2$

$0=15^2-2*5*s$

$s=15^2/10=22.5m$

If an object is moving at 15 m/s15 m/s over a surface with a kinetic friction coefficient of u_k=5 /gu_k=5 /g, how far will the object continue to move?