If an object is moving at $150 \frac{m}{s}$ $150 m/s$ over a surface with a kinetic friction coefficient of $u_{k} = \frac{15}{g}$ $u_k=15 /g$ , how much time will it take for the object to stop moving?

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If an object is moving at $150 \frac{m}{s}$ $150 m/s$ over a surface with a kinetic friction coefficient of $u_{k} = \frac{15}{g}$ $u_k=15 /g$ , how much time will it take for the object to stop moving?

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Answer 1 · 2016-02-04T12:14:19

I found $10 s$ $10s$

Explanation:

Have a look:
enter image source here

Answer 2 · 2016-02-04T12:33:15

$t = 10 s$ $t=10 s$

Explanation:

$F_{f} = u_{k} \cdot m \cdot g$ $F_f=u_k*m*g$
$F_f=15/cancel(g)*m*cancel(g)$
$F_f=15m$ $"friction force between object and surface"$
$"Kinetic energy of object is zero,if object stops"$
$Delta E_k=1/2*m*v^2$
$"Kinetic energy of object turns work ."$
$Delta E_k=F_f*x$
$1/2*cancel(m)*150^2=15*cancel(m)*x$
$2250cancel(0)=3cancel(0)*x$
$x=2250/3=750$ $"meters"$
enter image source here
$x="blue area"$
$750=(150*t)/2$
$150cancel(0)=15cancel(0)*t$
$t=150/15$
$t=10 s$

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If an object is moving at $150 \frac{m}{s}$ $150 m/s$ over a surface with a kinetic friction coefficient of $u_{k} = \frac{15}{g}$ $u_k=15 /g$ , how much time will it take for the object to stop moving?

2 Answers

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If an object is moving at 150 m/s150ms150 m/s over a surface with a kinetic friction coefficient of u_k=15 /guk=15gu_k=15 /g, how much time will it take for the object to stop moving?

2 Answers

Explanation:

Explanation:

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If an object is moving at $150 \frac{m}{s}$ $150 m/s$ over a surface with a kinetic friction coefficient of $u_{k} = \frac{15}{g}$ $u_k=15 /g$ , how much time will it take for the object to stop moving?