If an object is moving at $150 m/s$ over a surface with a kinetic friction coefficient of $u_k=15 /g$ , how far will the object continue to move?

Question

1456 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-07T07:51:45

The distance is $=150m$

The initial velocity is $u=150ms^-1$

The final velocity is $v=0ms^-1$

The distance is $s=?m$

The coefficient of friction is

$mu_k=F_r/N$

Let the mass be $=mkg$

Then

the normal reaction is $N=mgN$

So,

$F_r=mu_k*mgN$

$F=ma$

Therefore,

$ma=-mu_kmg$

The acceleration is $a=-mu_kg$ , the negative sign indicates a deceleration

The coefficient of kinetic friction is $mu_k=15/8$

We apply the equation of motion

$v^2=u^2+2as$

$0=150^2-2*15/g*g*s$

$s=150^2/30=750m$

If an object is moving at 150 m/s150 m/s over a surface with a kinetic friction coefficient of u_k=15 /gu_k=15 /g, how far will the object continue to move?