If an object is moving at $150 \frac{m}{s}$ $150 m/s$ over a surface with a kinetic friction coefficient of $u_{k} = \frac{2250}{g}$ $u_k=2250 /g$ , how far will the object continue to move?

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Answer 1 · 2016-05-28T09:09:34

$Delta x=5 m$

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$v_i=150 m/s" initial velocity"$
$u_k=2250/g" coefficient of friction"$

$"The object is decreased by the friction force"$

$F_f=u_k*m*g"$

$F_f=2250/cancel(g)*m*cancel(g)$

$F=m*a$

$2250*cancel(m)=cancel(m)*a$

$a=2250" " m/s^2$

$v_f^2=v_i^2-2*a*Delta x$

$"the final velocity of object will be zero if object stops."$

$0=v_i^2-2*a*Delta x$

$Delta x=v_i^2/(2*a)$

$Delta x=150^2/(2250)$

$Delta x=22500/(2*2250)$

$Delta x=5 m$

If an object is moving at 150 m/s150ms150 m/s over a surface with a kinetic friction coefficient of u_k=2250 /guk=2250gu_k=2250 /g, how far will the object continue to move?