If an object is moving at $18 m/s$ over a surface with a kinetic friction coefficient of $u_k=12 /g$ , how far will the object continue to move?

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Answer 1 · 2016-05-11T18:28:26

$x=13.5 " meters"$

$"1- Find the friction force :"$
$F_f=u_k*m*g" "u_k=12/g$

$F_f=12/cancel(g)*m*cancel(g)$

$F_f=12m$

$"2- Find deceleration using Newton's law :"$

$F_f=m*a$

$12cancel(m)=cancel(m)*a$

$a=12 m/s^2$

$"3- Find distance using the formula :"$

$v_f^2=v_i^2-2*a*x$

$"where :"$

$v_i:"initial velocity"$
$v_f:"final velocity=0"$
$a:"deceleration"$
$x:"distance"$

$0=18^2-2*12*x$

$324=24*x$

$x=324/24$

$x=13.5 " meters"$

If an object is moving at 18 m/s18 m/s over a surface with a kinetic friction coefficient of u_k=12 /gu_k=12 /g, how far will the object continue to move?