If an object is moving at 2ms over a surface with a kinetic friction coefficient of uk=17g, how far will the object continue to move?

1 Answer

x=217=0.11764 meter

Explanation:

Let x be the distance

From v2f=v20+2ax

Fk=ma Kinetic Frictional force
a=Fkm acceleration

Fk=μkFn Relation between Kinetic frictional force and the normal force

Fn=mg

x=v2fv202a

x=v2fv202(Fkm)

x=v2fv202((μkFn)m)

x=v2fv202((μkmg)m)

x=v2fv202(μkg)

vf=0 when it stops
v0=2 meter /second
μk=17g

x=v2fv202(μkg)
x=02222((17g)g)

x=434=217 meters

God bless....I hope the explanation is useful.