If an object is moving at 22 m/s over a surface with a kinetic friction coefficient of u_k=11 /g, how far will the object continue to move?

1 Answer
Jun 3, 2016

Delta x=22" "m" (area under graph)"

Explanation:

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u_k=11/g
v_i=22" "m/s

"Friction force: "F_f=u_k*m*g

F_f=11/g*m*g" ; "F_f=11m

F_f=m*a" ; "11*m=m*a" ; "a=11 " "m/s^2

v_f^2=v_i^2-2*a*Delta x

0=v_i^2-2*a*Delta x

v_i^2=2*a*Delta x

Delta x=v_i^2/(2*a)

Delta x=22^2/(2*11)

Delta x=22" "m" (area under graph)"