If an object is moving at 22 m/s over a surface with a kinetic friction coefficient of u_k=11 /g, how far will the object continue to move? Physics Forces and Newton's Laws Frictional Forces 1 Answer ali ergin Jun 3, 2016 Delta x=22" "m" (area under graph)" Explanation: u_k=11/g v_i=22" "m/s "Friction force: "F_f=u_k*m*g F_f=11/g*m*g" ; "F_f=11m F_f=m*a" ; "11*m=m*a" ; "a=11 " "m/s^2 v_f^2=v_i^2-2*a*Delta x 0=v_i^2-2*a*Delta x v_i^2=2*a*Delta x Delta x=v_i^2/(2*a) Delta x=22^2/(2*11) Delta x=22" "m" (area under graph)" Answer link Related questions Question #d6539 Question #242b7 Question #6bde4 Question #50c79 Question #a2018 Question #f7a62 Question #27931 Question #0b375 Question #d70af Question #dab6f See all questions in Frictional Forces Impact of this question 1632 views around the world You can reuse this answer Creative Commons License