Question

If an object is moving at `22 m/s` over a surface with a kinetic friction coefficient of `u_k=11 /g`, how far will the object continue to move?

Answer 1

`Delta x=22" "m" (area under graph)"`

Explanation:

`u_k=11/g`
`v_i=22" "m/s`

`"Friction force: "F_f=u_k*m*g`

`F_f=11/g*m*g" ; "F_f=11m`

`F_f=m*a" ; "11*m=m*a" ; "a=11 " "m/s^2`

`v_f^2=v_i^2-2*a*Delta x`

`0=v_i^2-2*a*Delta x`

`v_i^2=2*a*Delta x`

`Delta x=v_i^2/(2*a)`

`Delta x=22^2/(2*11)`

`Delta x=22" "m" (area under graph)"`