If an object is moving at $24 \frac{m}{s}$ $24 m/s$ over a surface with a kinetic friction coefficient of $u_{k} = \frac{6}{g}$ $u_k=6 /g$ , how far will the object continue to move?

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Answer 1 · 2017-11-10T01:36:26

$48 m$ $"48 m"$

Kind friction ( $f$ $f$ ) acting on object $= μ_kmg$

Retardation (a) of object $= f/m = μ_k g"$

Object will move to a distance $S$

$S = u^2 / "2a" = u^2 / (2mu_kg) = ("24 m/s")^2 / (2 × 6/cancel"g" xx cancel"g") = "48 m"$

If an object is moving at 24 m/s24ms24 m/s over a surface with a kinetic friction coefficient of u_k=6 /guk=6gu_k=6 /g, how far will the object continue to move?