If an object is moving at $3 \frac{m}{s}$ $3 m/s$ over a surface with a kinetic friction coefficient of $u_{k} = \frac{5}{g}$ $u_k=5 /g$ , how far will the object continue to move?

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If an object is moving at $3 \frac{m}{s}$ $3 m/s$ over a surface with a kinetic friction coefficient of $u_{k} = \frac{5}{g}$ $u_k=5 /g$ , how far will the object continue to move?

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Answer 1 · 2016-05-08T10:37:47

Here KE of the object = Work done against the force of kinetic friction
So $u_{k} \times m \times g \times d = \frac{1}{2} \cdot m \cdot v^{2}$ $u_kxxmxxgxxd=1/2*m*v^2$
Where $u_{k} = \frac{5}{g}$ $u_k= 5/g$
$m = mass, v = velocity$ $m="mass",v="velocity"$
$g="acceleration due to gravity=9.8m/s^2$
$d= "distance traversed"$

$u_kxxmxxgxxd=1/2*m*v^2$
$5/gxxcancel(m)xxgxxd=1/2*cancel(m)*v^2$
$d=v^2/10=3^2/10=0.9m$

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If an object is moving at $3 \frac{m}{s}$ $3 m/s$ over a surface with a kinetic friction coefficient of $u_{k} = \frac{5}{g}$ $u_k=5 /g$ , how far will the object continue to move?

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If an object is moving at $3 \frac{m}{s}$ $3 m/s$ over a surface with a kinetic friction coefficient of $u_{k} = \frac{5}{g}$ $u_k=5 /g$ , how far will the object continue to move?