If an object is moving at 6 m/s6ms over a surface with a kinetic friction coefficient of u_k=3 /guk=3g, how far will the object continue to move?

1 Answer
Feb 5, 2016

x=6 mx=6m

Explanation:

Delta E_k=1/2 .m. (v^2-0^2)
Delta E_k=1/2 .m. v²
"work doing by friction force=W"
W=Delta E_k
u_k . m. g. x=1/2 .m .v^2
3/cancel(g) .cancel(m) .cancel( g) . x=1/2 .cancel(m).6^2
6.x=36
x=36/6
x=6 m