Question

If an object is moving at `6 m/s` over a surface with a kinetic friction coefficient of `u_k=3 /g`, how far will the object continue to move?

Answer 1

`x=6 m`

Explanation:

`Delta E_k=1/2 .m. (v^2-0^2)`
`Delta E_k=1/2 .m. v²`
`"work doing by friction force=W"`
`W=Delta E_k`
`u_k . m. g. x=1/2 .m .v^2`
`3/cancel(g) .cancel(m) .cancel( g) . x=1/2 .cancel(m).6^2`
`6.x=36`
`x=36/6`
`x=6 m`