If an object is moving at $8 m/s$ over a surface with a kinetic friction coefficient of $u_k=9 /g$ , how far will the object continue to move?

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Answer 1 · 2018-05-05T06:21:35

The distance is $=3.56m$

The coeffcient of kinetic friction is $mu_k=9/g$

$mu_k=F_r/N$

Let the mass of the object be $=m kg$

Then,

The normal reaction is $N=mg N$

The frictional force is

$F_r=mu_kN=mu_kmg=9/g*mg=9mN$

$F=ma$

The acceleration is $a=F/m=F_r/m=-9m/m=-9ms^-2$

The initial velocity is $u=8ms^-1$

Apply the equation of motion

$v^2=u^2+2as$

The final velocity $v=0$

$0=64-2xx9xxs$

The distance is

$s=64/18=3.56m$

If an object is moving at 8 m/s8 m/s over a surface with a kinetic friction coefficient of u_k=9 /gu_k=9 /g, how far will the object continue to move?