If an object is moving at $8 m/s$ over a surface with a kinetic friction coefficient of $u_k=64 /g$ , how far will the object continue to move?

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Answer 1 · 2018-04-11T12:47:38

The distance is $=0.5m$

The coefficient of kinetic friction is

$mu_k=F_r/N$

Let the mass of the object be $=mkg$

Then,

The normal force $N=mg$

The acceleration due to gravity is $g=9.8ms^-2$

Therefore,

$F_r=mu_kN=mu_kmg$

$F=ma$

Therefore,

$ma=mu_kmg$

The decelleration is $a=mu_kg$

Apply the equation of motion

$v^2=u^2+2as$

$0=8^2-2mu_kgs$

$mu_k=64/g$

The distance is

$s=64/(2*64/g*g)=1/2=0.5m$

If an object is moving at 8 m/s8 m/s over a surface with a kinetic friction coefficient of u_k=64 /gu_k=64 /g, how far will the object continue to move?