If an object with a mass of 10 kg is moving on a surface at 3m/s and slows to a halt after 4 s, what is the friction coefficient of the surface? Physics Forces and Newton's Laws Frictional Forces 1 Answer ali ergin Mar 5, 2016 u_k~=0,076 Explanation: v_l=v_i-a t 0=3-4 a" "a=3/4 m/s^2 F_f=m a u_k cancel(m) g=cancel(m) a u_k *9,81=3/4 u_k~=0,076 Answer link Related questions Question #d6539 Question #242b7 Question #6bde4 Question #50c79 Question #a2018 Question #f7a62 Question #27931 Question #0b375 Question #d70af Question #dab6f See all questions in Frictional Forces Impact of this question 1353 views around the world You can reuse this answer Creative Commons License