If an object with a mass of $10 k g$ $10 kg$ is moving on a surface at $8 \frac{m}{s}$ $8 m/s$ and slows to a halt after $7 s$ $7 s$ , what is the friction coefficient of the surface?

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If an object with a mass of $10 k g$ $10 kg$ is moving on a surface at $8 \frac{m}{s}$ $8 m/s$ and slows to a halt after $7 s$ $7 s$ , what is the friction coefficient of the surface?

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Answer 1 · 2016-04-16T10:50:05

initial vel = $u = 8 \frac{m}{s}$ $u =8m/s$
final vel = $v = 0$ $v=0$
retardation = $a = ?$ $a =?$
time $t = 7 s$ $t = 7s$
$0 = u - a \times t$ $0=u-axxt$
$0 = 8 - a \times 7$ $0=8-axx7$
$a = \frac{8}{7} \frac{m}{s^{2}}$ $a=8/7m/s^2$
Now $μ m g = m \times a$ $mumg =mxxa$
$μ = \frac{a}{g} = \frac{8}{7} \times \frac{1}{9.8} = 0.117$ $mu =a/g=8/7xx1/9.8=0.117$

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If an object with a mass of $10 k g$ $10 kg$ is moving on a surface at $8 \frac{m}{s}$ $8 m/s$ and slows to a halt after $7 s$ $7 s$ , what is the friction coefficient of the surface?

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If an object with a mass of 10kg10 kg is moving on a surface at 8ms8 m/s and slows to a halt after 7s 7 s, what is the friction coefficient of the surface?

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If an object with a mass of $10 k g$ $10 kg$ is moving on a surface at $8 \frac{m}{s}$ $8 m/s$ and slows to a halt after $7 s$ $7 s$ , what is the friction coefficient of the surface?