If #b=sqrt(4ac-d)# Then What is #a^2-2b^2+c^2#?

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Answer 1 · 2018-05-20T14:57:30

#a^2-8ac+2d+c^2#

#b=sqrt(4ac-d)#
#a^2-2b^2+c^2#

substitute #b# into the second equation:

#a^2-2(sqrt(4ac-d))^2+c^2#

#a^2-2(4ac-d)+c^2#

#a^2-8ac+2d+c^2#