If CN- is a lewis base, can it also act as a lewis acid?

1 Answer
Feb 24, 2016

Actually, it could, but not often. Occasionally it acts as a Lewis acid to stabilize interactions with a transition metal, for instance.


CYANIDE COMPARES WELL WITH CARBON MONOXIDE

"CN"^(-)CN is isoelectronic with "CO"CO, and it can act as both a \mathbf(sigma) donor and \mathbf(pi) acceptor.

Its MO diagram looks somewhat like that of "CO":

Inorganic Chemistry, Miessler et al. Ch. 10.3.4, Figure 10.9

We can see the two electrons in the orbital labeled 3sigma, which is its HOMO. Also, its two 1pi^"*" antibonding orbitals are empty, which are its LUMOs.

Thus, it can donate electrons from its sigma bonding HOMO and/or accept electrons into its pi^"*" antibonding LUMOs. That makes it both a Lewis base and a Lewis acid for the respective reasons.

SOMETIMES, CYANIDE CAN BE A LEWIS ACID

One situation where "CN"^(-) acts like a Lewis acid is after it sigma bonds via its carbon onto a transition metal to form a metal-ligand complex, such as hexacyanochromate(III), i.e. ["Cr"("CN")_6]^(3-).

This behavior can be summarized in the following diagram which is based off of the angular overlap method, which is basically a simplified approach to approximate d-orbital splitting that ignores s and p interactions:

Inorganic Chemistry, Miessler et al. Ch. 10.4.1, Figure 10.22

As you can see, it gives a similar d-orbital splitting as one would get from Crystal Field Theory. (However, it gives an inaccurate representation of the ligand sigma MO energies!)

At first, "CN"^(-) uses its 3sigma HOMO to interact with the compatible d_(z^2) and d_(x^2-y^2) atomic orbitals of the transition metal and raises their energy when generating the two e_g^"*" orbitals (next to them is the label "z^2, x^2 - y^2").

"CN"^(-) ends up donating electrons to the metal in a \mathbf(sigma) destabilizing interaction. This is Lewis base behavior because it donates electrons.

Then, the 1pi^"*" antibonding LUMOs of "CN"^(-) also happen to be compatible with the d_(xy), d_(xz), and d_(yz) atomic orbitals of the transition metal and lowers their energy when generating the three t_(2g) orbitals (next to them is the label "xy,xz,yz").

This is done by accepting electrons from the metal in what's called a \mathbf(pi)-backbonding stabilization. This is Lewis acid behavior because it accepts electrons.

Here is the pi backbonding stabilization happening with "CO" and a transition metal's d_(xy) and d_(xz) orbitals.

Inorganic Chemistry, Miessler et al. Ch. 10.4.1, Figure 10.21

Overall, this increases the ligand field splitting energy, which one might call Delta_o for octahedral complexes, because the energy of the three now-lower t_(2g) orbitals decreased, and the energy of the two now-higher e_g^"*" orbitals increased, relative to the original, uncoordinated d atomic orbitals.

Because of the pi-acceptor, i.e. Lewis acid behavior of "CN"^(-), it is a very strong field ligand, and it often gives rise to "low spin" complexes where electrons are paired in the t_(2g) orbitals first before going into the higher-energy e_g^"*" orbitals.