If excess of AgNO_"3" solution is added to 100 ml of 0.024 M solution of dichlorobis (ethylene diamine) cobalt (III) chloride, how many moles of AgCl will be precipitated??

1 Answer
Aug 10, 2017

"0.0024 mols" of "AgCl".


Well, this is just a regular limiting reactants problem, with more complicated compounds. The only hurdle is figuring out what the dichlorobis(ethylenediamine)cobalt(III) charge is.

Dichlorobis(ethylenediamine)cobalt(III) chloride has:

  • two chloro ligands ("Cl"^(-)) in the inner coordination sphere.
  • two ethylenediamine ligands ("H"_2"N"-"CH"_2-"CH"_2-"NH"_2) in the inner coordination sphere.
  • a chloride ("Cl"^(-)) ligand coordinated on the outer coordination sphere.
  • cobalt(III), which has an oxidation state of... what is "III" in english?

The oxidation states add up as:

overbrace(2 xx (-1))^"dichloro" + overbrace(2 xx 0)^("bis"("en")) + overbrace((+3))^"cobalt(III)" = (+1)

Thus, it is written as...

overbrace(["CoCl"_2("en")_2])^(+1)"Cl"

The cis form is shown below.

![https://upload.wikimedia.org/](useruploads.socratic.org)

The ethylenediamine ligands are bidentate, sigma donor, strong-field ligands, so it is likely that this complex is a low-spin complex, making it relatively inert in the inner coordination sphere.

So, the reaction is probably going to be an outer-sphere, double-replacement reaction:

"AgNO"_3(aq) + ["CoCl"_2("en")_2]"Cl"(aq) -> "AgCl"(s) + ["CoCl"_2("en")_2]"NO"_3(aq)

The complex is clearly the limiting reactant, so...

"0.024 mol/L" xx "0.100 L" = "0.0024 mols complex"

The complex is 1:1 with "AgCl", so ulbb"0.0024 mols" of "AgCl" will be generated.