If $f (x) = 2 x^{2} + 5 \sqrt{x + 2}$ $f(x)=2x^2+5sqrt(x+2)$ how do you find f(0)?

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Answer 1 · 2016-11-24T16:53:10

$f (0) = \pm 5 \sqrt{2}$ $f(0)=+-5sqrt2$

For $f (0)$ $f(0)$ , simply substitute $x = 0$ $x=0$ into the function.

And thus, $f (0) = 2 {(0)}^{2} + \pm 5 \sqrt{0 + 2} = \pm 5 \sqrt{2}$ $f(0)=2(0)^2++-5sqrt(0+2)=+-5sqrt2$

If f(x)=2x2+5√x+2f(x)=2x^2+5sqrt(x+2) how do you find f(0)?